
#1
Jan1611, 08:53 AM

P: 6

From my Linear Algebra course I learned tha and eigenvalue w is an eigenvalue if it is a sollution to the system:
Ax=wx, where A= square matrix, w= eigenvalue, x= eigenvector. We solved the system by setting det(AI*w)=0, I=identity matrix Now in an advanced course I have come upon the equation system Ax=wKx, A= square matrix, x= vector, K= square matrix, w= scalar. They say we can solve it by setting (AwK)x=0, and they call this an eigenvalueproblem. And say we can solve it by settig det(AwK)=0. My question: Is this really an eigenvalueproblem? I looked in my book and on wikipedia, and there they both say that eigenvalue/vector prblems is Ax=wx, in my problem I have a matrix on both sides. Ax=wKx, so can w then be a eigenvalue? I appreciate the help. 



#2
Jan1611, 09:00 AM

P: 876

w is called a generalised eigenvalue of A and K and x is a generalised eigenvector. This form comes up frequently in differential equations. Click here to read more.



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