Finding the Limit of $\frac {\sqrt{x} - x^2} {1 - \sqrt{x}}$

[check]

I've can't seem to get this:

$$\lim_{\substack{x\rightarrow 1}} \frac {\sqrt{x} - <br /> x^2} {1 - \sqrt{x}}$$

I know it equals 3... I got that from the using numbers close to 1 method and from the dervative of the top over the derivative of the bottom method... trouble is, I don't think that's how he wants us to find the answer because we haven't learned the derivative method yet. any help would be awesome.

 

[arildno]

Set:
$$a=\sqrt{x}$$
Then:
$$\frac{\sqrt{x}-x^{2}}{1-\sqrt{x}}=a\frac{1-a^{3}}{1-a}$$
Does that help?

 

[check]

YES! Oh sweet, thanks a lot!