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Coprime polynomials

by Bleys
Tags: coprime, polynomials
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Bleys
#1
Jan23-11, 06:51 AM
P: 74
Let K be a subfield of C, the field of complex numbers, and f an irreducible polynomial in K[X].
Then f and Df are coprime so there exist a,b in K[X] such that af + bDf = 1 (D is the formal derivative operator). Now what I don't understand is why this equation implies f and Df are coprime when viewed over C[X]. Doesn't f split into linear factors over C[X] so is it not possible that a factor divides Df (not always but could happen?).
Although if I write f in linear factors and then compute Df I can see that no linear factor of f divides it, but it does if one of the linear factors is repeated?
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adriank
#2
Jan23-11, 12:03 PM
P: 534
Certainly if there exist a and b in K[X] such that af + bDf = 1, then there exist a and b in C[X] such that af + bDf = 1. This is equivalent to saying that none of the linear factors of f in C[X] are repeated (if there was such a linear factor, it would divide both f and Df).


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