What is the force on the handle in a statics problem using Excel?

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SUMMARY

The discussion focuses on solving a statics problem involving the calculation of the force on a handle using Excel. The problem requires graphing the force on the handle against varying angles from -30 to 30 degrees, with the force being perpendicular to the handle and positioned 500mm from point A. Key equations include M*g*Sin(Theta) for the force necessary to maintain equilibrium along the plane and M*g*Cos(Theta) for the normal reaction when considering the angle from the vertical. The discussion also highlights the importance of simplifying the free body diagram to identify the forces acting on the handle.

PREREQUISITES
  • Understanding of statics and equilibrium principles
  • Familiarity with Excel for graphing and calculations
  • Knowledge of free body diagrams and force analysis
  • Basic trigonometry, specifically sine and cosine functions
NEXT STEPS
  • Learn how to create dynamic graphs in Excel to visualize force vs. angle
  • Study the principles of free body diagrams in statics
  • Explore the concept of equilibrium and the equations ΣF=0 and ΣM=0
  • Investigate the effects of varying angles on force calculations in statics problems
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Students studying statics, engineers working on mechanical systems, and anyone interested in applying Excel for solving physics problems related to forces and equilibrium.

Double A
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I have a problem in statics that I must use excel to do and my instructor modified the given question in a few ways to allows to use the capabilities of excel to find what the question asks for.

http://herograw.com/5-51.JPG

These are my instructors additions:
The 30 degree angle will be varying from -30 to 30 degrees (0 to 30 degrees is also fine, if you note the symmetry). In order to maintain equilibrium at all those possible angles, we will need to apply a force on the handle. Force on the handle vs. angle is what we are going to graph. The force on the handle is always perpendicular to the handle and is positioned 500mm from point A.

If the whole excel approach sounds confusing then please help in solving the original question. That way I can use that method in solving the question the way my instructor expects.
 
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Resolve the weight of the object along and perpendicular to the angular plane, given the angle from the horizontal is theta...

then the along the place component of theta would be M*g*Sin(Theta) which would be your force necessary to hold the body back...

What would be the normal reaction of the place?? (:-)

Anyways, so your curve essentially would be a sin curve...

PS: If you consider the angle to be from the vertical then the equation will change to hace M*g*Cos(theta).. so that's where symmetry comes in...

Cos(a) = Cos(-a) ... happy?
 
I'm not all that clear about what you said to do.

In class today I was given an extension on this problem.

I also found that the free body diagram that I was using was a little complicated and the only forces acting on the handle is the applied force and the force caused by the spring. I'm a little confused in how to find the force caused by the spring and which [tex]\Sigma F=0[/tex] and [tex]\Sigma M=0[/tex] equations to use.
 
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