Solving Physics Equation for v: Mistakes and Solutions

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SUMMARY

The discussion centers on solving the physics equation for velocity (v) in the context of projectile motion. The original equation presented is 20 = (v)sin(35)*(159/v) + 0.5(-9.8)(159/v)^2. The correct manipulation leads to v^2 = (sin(35)(159) + 0.5(-9.8)(159^2))/20. A critical mistake identified is the failure to multiply the first term on the right-hand side by v^2 during the algebraic manipulation. The expected solution for v is 42.

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Warwick
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Okay, I have this equation and I want to solve for v, so basicaly it's really just an algebra problem.

Original equation
20=(v)sin(35)*(159/v)+.5(-9.8)(159/v)^2

v^2=(sin(35)(159)+.5(-9.8)(159^2))/20<-- what I do, then I take it to the ^(1/2)

The answer should be 42, but I keep getting crazy answeres. What am I doing wrong?

thanks
 
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When you multiplied through by v^2, you forgot to multiply the 1st term on the RHS by v^2.

Claude.
 
Can anyone help me with this question?

Use the Continuity Equation to explain how jet engines provide a forward thrust for an airplane.


I don't think only the actual equation would help to explain fully the question but I really need some specific explanation for this.
 

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