Bow & Arrow - Impulse-Momentum Theorem


by dandy9
Tags: archery, arrow, impulse, momemtum
dandy9
dandy9 is offline
#1
Feb17-11, 06:25 PM
P: 28
1. The problem statement, all variables and given/known data
A 64.2kg man fires a .3kg arrow. The arrow is measured to have a velocity of 63m/s by a stationary bystander. All these happen while the archer sliding backwards at -.26m/s. What will be his velocity (in the x-direction) after firing this arrow?

2. Relevant equations
pbefore = pafter


3. The attempt at a solution
I used the eq'n m1v1 + m2v2 = m1v1' + m2v2'
I was able to solve the left side to be 2.208.
But I'm unsure of what to use for v2' on the right side... The arrow surely doesn't still fly at 63m/s right? Nor does it come to rest?

Thank you!
Phys.Org News Partner Science news on Phys.org
Simplicity is key to co-operative robots
Chemical vapor deposition used to grow atomic layer materials on top of each other
Earliest ancestor of land herbivores discovered
ashishsinghal
ashishsinghal is offline
#2
Feb18-11, 04:24 AM
P: 460
v2' will be 63m/s.why do you have a doubt here. what have you taken as v2


Register to reply

Related Discussions
Use the Impulse-Momentum Theorem Introductory Physics Homework 3
Impulse-Momentum Theorem Introductory Physics Homework 1
Impulse-Momentum Theorem Introductory Physics Homework 1
impulse momentum theorem Introductory Physics Homework 10
Impulse-Momentum Theorem Introductory Physics Homework 2