Max Angle for Parking on Steep Hill: Coefficient of Friction Calculation

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Homework Help Overview

The discussion revolves around calculating the maximum angle at which a car can be parked on a steep hill, given the coefficient of friction between hard rubber and pavement. Participants explore the relationship between forces acting on the car, particularly focusing on friction and gravitational components.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants suggest assigning a mass to the car and conducting a forces analysis to determine the friction force and gravitational components. There are questions about the equations involved, particularly regarding the equilibrium condition and the relationship between friction and gravity.

Discussion Status

Some guidance has been offered regarding the setup of equations for analyzing forces, with participants discussing how to express the conditions for equilibrium. Multiple interpretations of the problem are being explored, particularly in relation to the forces acting on the car on an incline.

Contextual Notes

There is a noted lack of specific information, such as the weight of the car, which some participants mention as a challenge in solving the problem. Additionally, one participant expresses uncertainty about terminology related to skidding.

dabouncerx24
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The coefficient of friction between hard rubber and normal street pavement is about 0.8. On how steep a hill (max angle) can you leave a car parked?


I have no idea how to do it since it doesn't give you the weight or anything.
 
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Let's see, so why don't you assign the car a mass m, and then start doing the forces analysis, and see what will be the force of friction be, and you know the force of gravity (a component of it) will be the force making the car fall, so if the friction force equals that force they will cancel and the car won't fall, then you can find the angle for that case.
 
Forces analysis..meaning the Friction Force = Ums + Fn equation??
The component of force of gravity will simply be Fwsin? right.


I am so bad in physics...
 
Well on

y-axis:

[tex]N = mgcos\theta[/tex]

on x-axis:

If there's not movement
[tex]-mgsin\theta + \mu_{s}mgcos\theta = 0[/tex]

if

[tex]\mu_{s}mgcos\theta = mgsin\theta[/tex]

Then the block should be at equilibrium, and the angle theta should be the max angle.

solve for theta (i simplifyed for you, and remember your trigonometry)

[tex]\mu_{s}cos\theta = sin\theta[/tex]
 
thank you very much
 
Welcome to PF!, it was a pleasure to be of assistance, also don't discourage yourself on physics, the universe we live is a very interesting place, where many theories tries to explain how it works. Just imagine the problems, understand the concepts... and you should do ok :smile:
 
I'm sure I will get better as time progress, thank you for the warm welcome for I am sure I will be coming here A LOT during the school year.

Well...another problem already.

A car can decelerate at -5.10 m/s^2 w/o skidding when coming to rest on a level road. What would its deceleration be if the road were inclined at 12 degrees upward.

I'm guessing the sigma F equation comes into play here...? Thats all I know... :frown:
 
Last edited:
i'm sorry, I'm spanish what's skidding?
 
Cyclovenom,
skidding means sliding on a surface ...

dabouncer,
for the first case of level road,
what parameters can u find out ? (note : the car comes to rest)
whatever parameters u find for this case , apply it to second case and find its deceleration? ...

-- AI
 

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