Solving The Equation: x^2 + y^2 = 16 and xy = 8

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Homework Help Overview

The discussion revolves around solving the equations x^2 + y^2 = 16 and xy = 8, specifically focusing on finding the value of (x+y)^2. Participants are exploring the relationships between these equations and the implications of their values.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to calculate (x+y)^2 using the given equations and are questioning the correctness of their initial calculations. There is a focus on the relationship between the variables and the derived expressions.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's calculations. Some have pointed out errors in the initial assumptions and calculations, while others are seeking clarification on the relationships between the variables.

Contextual Notes

There appears to be confusion regarding the value of xy, with one participant mistakenly stating it as 18 instead of 8, which may affect the calculations being discussed.

Dooga Blackrazor
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A Question

1. If x^2 + y^2 = 16 and xy = 8 then what is (x+y)^2 ?

32, correct?

90?
120?
1260?
150?
 
Last edited:
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1. Incorrect; think again.
 
I meant to put 32, whoops.
 
Still incorrect..
 
(x+y)^2 = x^2 +2xy + y^2

xy = 8
x^2 + y^2 = 16

2(8) = 16 + 16 = 32

Where am I going wrong?
 
Well, from your first post, it says xy=18..
 
Ah, thanks.
 

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