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dual vector bundle E* is isomorphic to Hom(E, MXR) |
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| Mar4-11, 02:40 AM | #1 |
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dual vector bundle E* is isomorphic to Hom(E, MXR)
As E* is defined in some book as Hom(E, MXR). What could be the isomorphism between dual vector bundle E* and Hom(E, MXR)?
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| Mar4-11, 08:04 AM | #2 |
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So how do you define E*?
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| Mar4-11, 11:39 AM | #3 |
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That's the part that is confusing to me. So I have checked on wikipedia, and it defines E*=Hom(E,MXR). However, there is a natural isomorphism on bundle that is Hom(E,E')=E*(direct sum)E, therefore I am wondering if I can use this isomorphism to get the result that E* is isomorphic to E*(direct sum) MXR and thus isomorphic to Hom(E, MXR)?
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| Mar4-11, 05:15 PM | #4 |
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Recognitions:
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dual vector bundle E* is isomorphic to Hom(E, MXR)
Still, how does your question even make sense if you have no definition of E*? For me, the dual of a vector bundle E is obtained from E by taking fiber-wise duals, i.e. the fibers of E* are the vector space duals of the fibers of E. Of course, the dual of a k-vector space Ep is Ep*=Hom_k(E,k).
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| Mar5-11, 09:25 PM | #5 |
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I'm failing to see how it's not tautological.
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