| New Reply |
Proving that the product rule for differentiating products applies to vectors |
Share Thread |
| Mar6-11, 01:01 AM | #1 |
|
|
Proving that the product rule for differentiating products applies to vectors
If r and s are vectors that depend on time, prove that the product rule for differentiating products applies to r.s, that is that:
d/dt (r.s) = r. ds/dt + dr/dt .s -- I'm not entirely sure how I'm supposed to go about proving this, can anyone point me in the right direction, please? 1. The problem statement, all variables and given/known data |
| Mar6-11, 06:11 AM | #2 |
|
|
Start with
[tex]\frac{d}{dt} (\vec{r}\cdot\vec{s}) = \frac{d}{dt}(r_x s_x + r_y s_y + r_z s_z)[/tex] |
| New Reply |
Similar discussions for: Proving that the product rule for differentiating products applies to vectors
|
||||
| Thread | Forum | Replies | ||
| Derivatives. Product rule with 3 products | Calculus & Beyond Homework | 3 | ||
| Proving perpendicular vectors using Dot Product | Calculus & Beyond Homework | 1 | ||
| Proving that a certain f(x) can't be zero by differentiating | Calculus | 6 | ||
| Differentiating Products | Differential Equations | 2 | ||
| Proving the Product rule | Calculus | 12 | ||