Rocket Motion: Solving the Rocket Equation for Lift-Off

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Homework Help Overview

The problem involves calculating the time it takes for a rocket to lift off after its engines are fired, given its initial mass, fuel burn rate, and exhaust velocity. The context is rooted in rocket motion and the application of the rocket equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss variations of the rocket equation and its application, questioning the dimensional correctness of the original equation used. Some suggest equating the force produced by the rocket to its weight as a potential approach.

Discussion Status

The discussion is active, with participants providing hints and alternative methods for approaching the problem. There is no explicit consensus on the best method, and multiple interpretations of the rocket equation are being explored.

Contextual Notes

Participants note constraints such as the dimensional correctness of equations and the need for numerical solutions within a specific time interval. There is also mention of the original mass and the rate of mass loss as critical factors in the calculations.

SlickJ
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This question was posed in class the other day for extra credit:

A rocket with initial mass 70000kg burns fuel at a rate of 250kg/s; it has an exhaust velocity of 2500m/s. If the rocket is at rest, how long after the engines fire will the rocket lift off?

I've been trying to solve it using some variation of the rocket equation:
v=v(exhaust) * ln(M(0)/M(t)) - gt
but to no success.
Any hints or help would be greatly appreciated
 
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There is a problem with the equation you are using
it is r (rate of burning the fuel) for g you used, also it is dimensionally incorrect we can have log of only natural numbers.
If it works that's Ok, otherwise try by equating force by the ejected gass to mass of rocekt at the moment.
 
SlickJ said:
This question was posed in class the other day for extra credit:

A rocket with initial mass 70000kg burns fuel at a rate of 250kg/s; it has an exhaust velocity of 2500m/s. If the rocket is at rest, how long after the engines fire will the rocket lift off?

I've been trying to solve it using some variation of the rocket equation:
v=v(exhaust) * ln(M(0)/M(t)) - gt
but to no success.
Any hints or help would be greatly appreciated

Be careful. The equation of your rocket is:

[tex]v=2500\cdot ln\Big(\frac{70000}{70000-250t}\Big)-9.8t[/tex]

There is an interval of velocities 0<t<47.9 s in which v<0. The rocket will start to lifting off when v>0 or t>47.9 s. (solve numerically the equation v=0, you will obtain t=0 and t=47.9 s).
 
Thanks both of you for your help, very much appreciated.
 
I think you're all making this much too complicated.
Just calculate the force the rocket produces using the equation force = change in momentum / time, with knowledge of the fact that momentum is mass times velocity. The weight of the rocket is given by acceleration due to gravity x (original mass of rocket - (rate at which the rocket loses mass x time). Set the weight of the rocket to equal the its force of propulsion (which you already calculated) and solve for time. At that time, the force of thrust will balance the rocket's weight and immediately afterwards it will start lifting off.
 
Last edited:
I get about 25 seconds.
 

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