Are Even and Odd Functions Orthogonal?

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    Functions Orthogonality
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SUMMARY

The discussion confirms that even and odd functions are orthogonal under the inner product defined as = ∫-aa f(x)g(x)dx. An odd function satisfies the condition f(x) = -f(-x), while an even function satisfies f(x) = f(-x). The participants established that the product of an even function and an odd function is odd, and that the integral of an odd function over the interval [-a, a] equals zero, reinforcing the orthogonality concept.

PREREQUISITES
  • Understanding of even and odd functions
  • Familiarity with integral calculus
  • Knowledge of inner product spaces
  • Basic concepts of mathematical proofs
NEXT STEPS
  • Study the properties of inner products in function spaces
  • Explore the proof of orthogonality for trigonometric functions
  • Learn about Fourier series and their relationship with even and odd functions
  • Investigate applications of orthogonal functions in signal processing
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Mathematicians, physics students, and anyone interested in functional analysis or signal processing who seeks to deepen their understanding of orthogonality in functions.

theFuture
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We were doing examples in class today and showed that sin and cos were orthogonal functions. In general, is true that even and odd functions are orthogonal? I was unsure where a proof of this might begin, mostly how to generalize the notion of an even or odd function.
 
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This depends on what your "inner product" is.

Let's assume it is

[tex]<f,g> = \int_{-a}^a f(x)g(x)dx[/tex]

an odd function is one that satisfies f(x) = -f(-x) an even one satisfies f(x)=f(-x)

1. show that the product of an even and an odd function is odd
2. show that the integral of an odd function over any interval [-a,a] is zero.
 
Thanks. Now that I see it like that I can't believe I couldn't come up with that.
 

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