How Should Gravity Impact Calculations of Speed in Spring Compression Problems?

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Homework Help Overview

The discussion revolves around a physics problem involving a block dropped onto a vertical spring, focusing on the calculations of speed and the role of gravitational potential energy in spring compression scenarios.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply energy conservation principles but questions their setup and calculations. Some participants suggest considering the gravitational potential energy in the context of the spring's compression.

Discussion Status

Participants are exploring the implications of gravitational potential energy on the block's speed just before it contacts the spring. There is an ongoing examination of how energy transformations occur during the compression process, with no explicit consensus reached yet.

Contextual Notes

The problem involves a block of mass 250 g and a spring constant of 2.2 N/cm, with a specified compression distance of 14 cm. Assumptions include negligible friction and the need to account for gravitational effects.

AtlBraves
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I am having trouble with this part of the problem. I set it up like this: -.5*m*v^2 = -.5*k*d^2 so v = sqrt((k*d^2)/m) = sqrt((220*.14^2)/.25) = 4.15 m/s. What am I doing wrong?

A 250 g block is dropped onto a relaxed vertical spring that has a spring constant of k = 2.2 N/cm (Figure 7-42). The block becomes attached to the spring and compresses the spring 14 cm before momentarily stopping.

(c) What is the speed of the block just before it hits the spring? (Assume that friction is negligible.)

07_41.gif
 
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Possibly, you should take into account the change in gravitational potential energy as well.
 
I don't understand.
 
while the spring is compressing, gravity is still adding kinetic energy, even as the spring is taking it away. so you should see how much gravitational potential energy has been included after the 14 cm compression, and take that into account with your equation
 

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