Energy in Circuits: The power lost to joule heating.


by BillJ3986
Tags: circuits, energy, heating, joule, lost, power
BillJ3986
BillJ3986 is offline
#1
Mar14-11, 04:51 PM
P: 7
1. The problem statement, all variables and given/known data
The aluminum cable of a high-voltage transmission line carries a current 600A. The cable is 60km long, and it has a diameter of 2.5 cm. What is the power lost to Joule heating in this cable?


2. Relevant equations
Should I use the equation V=1/(4piEo)integral(dq/r) to find the potential? And in saying that I also need to find the charge in order to find the potential difference? Do I have to use Gauss's Law to find the charge?


3. The attempt at a solution
I know that the equation to find the power lost to joule heating is P=I^2R
in order to find the resistance, I solved solved for the potential difference using V=1/(4piEo)(q/r), I assumed that since the cable is aluminum that the Q= 1.6x10^-19C. my answer for potential difference is 1.2x10^-7 which I know is wrong.
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
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BillJ3986
BillJ3986 is offline
#2
Mar14-11, 06:06 PM
P: 7
I already answered the question. I had to look up resistivity for aluminum since the cable is made up of aluminum, and use the equation R=P(L/A). After finding the resistance. I was able to find out the power lost to Joule heating by using P=I^2(R). P=600^2(3.42)= 1.2X10^6W.


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