A few circuit analysis questions.

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SUMMARY

The discussion focuses on solving a circuit analysis problem involving a 2 Amp current source and a 1 micro-Farad capacitor. The user, Nik, applies the superposition theorem to determine the steady state DC current in a 20 Ohm resistor. It is concluded that once the steady state is reached, the capacitor is fully charged, resulting in no current flowing into it, allowing for its effects to be ignored. The calculated currents are 0.4A from the current source and 0.1A from the voltage source.

PREREQUISITES
  • Understanding of circuit analysis principles, specifically superposition theorem.
  • Familiarity with steady state conditions in RC circuits.
  • Knowledge of current and voltage sources in electrical circuits.
  • Basic skills in using circuit simulation tools like MicroCap.
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  • Study the superposition theorem in greater detail, focusing on its application in circuit analysis.
  • Learn about the behavior of capacitors in steady state and transient conditions.
  • Explore circuit simulation techniques using MicroCap for visualizing circuit behavior.
  • Investigate the effects of different resistor values on current distribution in circuits.
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Electrical engineering students, circuit designers, and anyone involved in circuit analysis and simulation will benefit from this discussion.

SpeedBird
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hello there,
i'm wondering how to go about solving this problem
A diagram of the circuit can be seen here
http://www.compsoc.nuigalway.ie/~filter/images/circuit.gif
(i threw it together in microcap) the pulse sourse is actually
meant to be a 2Amp current source. the capacitor
has a value of 1micro-Farad.

By using superposition i have to find the steady state DC
current flowing in the 20 Ohm resistor. i could usually do
this easy but the capacitor is throwing me off. I am assuming
that once a steady state has been reached, the capacitor
will be fully charged and no current will actually be flowing
into it right? if this is the case.. i decided that i could ignore
its effects.. because it should really have any. and this
appears to work. i don't know if its a fluke or not though.

the answers are 0.4A flows in the 20 Ohm resistor due to
the current source and 0.1A flows in the 20 Ohm resistor
due to the voltage source.

any ideas on how to go about this would be welcome.

i need my mind to be put at rest :-) cheers, Nik
 
Last edited by a moderator:
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Since your link is broken, the circuit can't be seen so no help can be given
 

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