## EMF induced in a loop/wire

1. The problem statement, all variables and given/known data
Hey guys,
This is just a qualitative question.
So assume I have a massive super large magnetic field, and pull a straight, isolated conducting wire sideways through it with constant velocity. I know that the EMF induced is given by
emf = Blv where
l is the length of the conductor
B the magnetic field strength
and v the velocity with which the wire moves

But say I have a square loop entirely in the field, and move it again with velocity v (it still remains entirely in the field)
Is there still emf induced? By Faraday's law, there's no change in flux, so hence there should be no emf. By I just don't know why.
I mean if emf is induced even for an isolated straight wire, why isn't it for a square loop?
I'm thinking it's kind of because the 2 vertical sides of the square loop both have charges trying to move up/down them (depending on the direction B and which way the loop moves), so they kind of "crash" into each other at the top and bottom edges and cancel out each other?
I'm sorry if it's kind of confusing, but does anyone know?

Thank you very much!
 PhysOrg.com science news on PhysOrg.com >> Galaxies fed by funnels of fuel>> The better to see you with: Scientists build record-setting metamaterial flat lens>> Google eyes emerging markets networks
 Recognitions: Gold Member when a straight wire moves, it behaves as though the area enclosed by an imaginary loop with the wire as one edge is increasing. but for a square loop, the area remains constant.

 Tags conductor, electromagnetism, emf, loop, wire
 Thread Tools

 Similar Threads for: EMF induced in a loop/wire Thread Forum Replies Introductory Physics Homework 4 Introductory Physics Homework 0 Introductory Physics Homework 2 Classical Physics 7 Introductory Physics Homework 2