Solving the Normal Force of a 74 kg Chemistry Student on a Ferris Wheel

[Naeem]

Hi folks,

Would appreciate any help with this problem

A chemistry student with a mass of 74 kg is riding a steadily moving Ferris wheel. When she is at the top of the Ferris wheel, the normal force from the seat on to her body has a magnitude of 556 N.

a)What is the magnitude of the normal force on her body when she is at the bottom of the Ferris wheel's arc?

I figured out the answer to this question,

But I am stuck with part B
b ) What would the normal force be on the student at the top of the wheel if the wheel's velocity were doubled?
Plz help

Thanks a million!

 

[vsage]

Consider the force on her. You got mg pulling down, negative centripetal force trying to make her leave her seat and the resulting force is 556N downward because the normal force from the seat is 556N. doubling the velocity increases the negative centripetal force by what factor?

 

[Naeem]

Consider the force on her. You got mg pulling down, negative centripetal force trying to make her leave her seat and the resulting force is 556N downward because the normal force from the seat is 556N. doubling the velocity increases the negative centripetal force by what factor?

I figured out that if velocity is doubled mv^2/R increases by a factor of 4.

but, how do I setup the equation.

 

[Naeem]

I beg you folks to help me on how to setup the equation for the 2nd part.

Thanks,

Naeem

 

[Naeem]

Finally got this one. Thanks anyway