Verifying Homework Equations: 4 Variables

Click For Summary
SUMMARY

The discussion focuses on verifying the calculations for homework equations involving shear stress, bending stress, and torque in a mechanical engineering context. Key equations include shear stress τ = 4V/3A, bending stress σ_b = Mc/I, and torque τ = Tr/J. The user calculated maximum shear stress as 29.5 KPa and maximum bending stress as 294.7 KPa, both of which were confirmed as correct by other forum members. The calculations were performed using standard formulas for shear and bending in cylindrical structures.

PREREQUISITES
  • Understanding of shear and bending stress equations
  • Familiarity with torque calculations in mechanical systems
  • Knowledge of integration for determining moment functions
  • Basic principles of mechanics of materials
NEXT STEPS
  • Study the derivation of shear and bending stress equations in mechanical engineering
  • Learn about the application of the moment of inertia in structural analysis
  • Explore advanced topics in mechanics of materials, such as fatigue analysis
  • Review integration techniques for calculating area under curves in engineering contexts
USEFUL FOR

Mechanical engineering students, educators, and professionals preparing for exams or seeking to reinforce their understanding of stress and torque calculations in structural analysis.

temaire
Messages
275
Reaction score
0

Homework Statement



rc7qe9.png


Homework Equations



[tex]\tau=\frac{4V}{3A}[/tex]

[tex]\sigma_b=\frac{-Mc}{I}[/tex]

[tex]\tau=\frac{Tr}{J}[/tex]

[tex]J=\frac{\pi r^4}{2}[/tex]

[tex]I=\frac{\pi r^4}{4}[/tex]

The Attempt at a Solution



a)
2us7hg2.png


[itex]-V(x) + R_y = 0[/itex]
[itex]V(x) = R_y[/itex]
[itex]V(x) = 1000[/itex]

[itex]M(x) = \int V(x)dx[/itex]
[itex]M(x) = 1000x[/itex]

[itex]T(x) = P(0.4)[/itex]
[itex]T(x) = 400[/itex]

ddi683.png


[itex]V(x) - 1000 = 0[/itex]
[itex]V(x) = 1000[/itex]

[itex]M(x) = \int V(x)dx[/itex]
[itex]M(x) = 1000x[/itex]

[itex]T(x) = 0[/itex]

b)
[tex]\tau_{max} = \frac{4V}{3A}[/tex]

[tex]\tau_{max} = \frac{4*1000}{3*\pi*0.12^2}[/tex]

[tex]\tau_{max} = 29.5 KPa[/tex]

Coordinates: From (0,-0.12,0)m to (0,0.12,0)m

c)
[tex]\sigma_b=\frac{Mc}{I}[/tex]

[tex]\sigma_b=\frac{Mc}{\frac{\pi r^4}{4}}[/tex]

[tex]\sigma_b=\frac{1000*0.4*0.12}{\frac{\pi * 0.12^4}{4}}[/tex]

[tex]\sigma_b=294.7 KPa[/tex]

[tex]\sigma_{Max,tensile}=294.7 KPa[/tex] at (0,0,0.12)m

[tex]\sigma_{Max,compressive}=-294.7 KPa[/tex] at (0,0,-0.12)m

d)
[tex]\tau=\frac{Tr}{J}[/tex]

[tex]\tau=\frac{Tr}{\frac{\pi r^4}{2}}[/tex]

[tex]\tau=\frac{1000*0.4*0.12}{\frac{\pi *0.12^4}{2}}[/tex]

[tex]\tau=147.4 KPa[/tex]

Coordinates: From (0,-0.12,0)m to (0,0.12,0)m


Is my work correct?
 
Physics news on Phys.org
Guys, I have a final exam on this material tomorrow. Any help would be appreciated.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
12K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 0 ·
Replies
0
Views
3K