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Homework Statement
Homework Equations
[tex]\tau=\frac{4V}{3A}[/tex]
[tex]\sigma_b=\frac{-Mc}{I}[/tex]
[tex]\tau=\frac{Tr}{J}[/tex]
[tex]J=\frac{\pi r^4}{2}[/tex]
[tex]I=\frac{\pi r^4}{4}[/tex]
The Attempt at a Solution
a)
[itex]-V(x) + R_y = 0[/itex]
[itex]V(x) = R_y[/itex]
[itex]V(x) = 1000[/itex]
[itex]M(x) = \int V(x)dx[/itex]
[itex]M(x) = 1000x[/itex]
[itex]T(x) = P(0.4)[/itex]
[itex]T(x) = 400[/itex]
[itex]V(x) - 1000 = 0[/itex]
[itex]V(x) = 1000[/itex]
[itex]M(x) = \int V(x)dx[/itex]
[itex]M(x) = 1000x[/itex]
[itex]T(x) = 0[/itex]
b)
[tex]\tau_{max} = \frac{4V}{3A}[/tex]
[tex]\tau_{max} = \frac{4*1000}{3*\pi*0.12^2}[/tex]
[tex]\tau_{max} = 29.5 KPa[/tex]
Coordinates: From (0,-0.12,0)m to (0,0.12,0)m
c)
[tex]\sigma_b=\frac{Mc}{I}[/tex]
[tex]\sigma_b=\frac{Mc}{\frac{\pi r^4}{4}}[/tex]
[tex]\sigma_b=\frac{1000*0.4*0.12}{\frac{\pi * 0.12^4}{4}}[/tex]
[tex]\sigma_b=294.7 KPa[/tex]
[tex]\sigma_{Max,tensile}=294.7 KPa[/tex] at (0,0,0.12)m
[tex]\sigma_{Max,compressive}=-294.7 KPa[/tex] at (0,0,-0.12)m
d)
[tex]\tau=\frac{Tr}{J}[/tex]
[tex]\tau=\frac{Tr}{\frac{\pi r^4}{2}}[/tex]
[tex]\tau=\frac{1000*0.4*0.12}{\frac{\pi *0.12^4}{2}}[/tex]
[tex]\tau=147.4 KPa[/tex]
Coordinates: From (0,-0.12,0)m to (0,0.12,0)m
Is my work correct?