Solve for Length of Friction-Ridden Ice Patch | Work-Energy Theorem Hint

  • Thread starter Thread starter kingsean
  • Start date Start date
  • Tags Tags
    Work-energy
Click For Summary

Homework Help Overview

The problem involves a skater on a frictionless ice rink who encounters a rough patch that reduces her speed due to friction. The task is to find the length of this rough patch using the work-energy theorem.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using the work-energy theorem, focusing on kinetic energy and work done by friction. There are attempts to express the problem in terms of mass and questions about the calculations of final velocity and energy.

Discussion Status

Some participants have provided guidance on how to approach the problem using mass as a variable and the relationship between initial and final kinetic energy. Others are sharing their calculations and results, indicating a range of interpretations and outcomes without a clear consensus.

Contextual Notes

There is mention of a specific numerical answer from the textbook, which may influence participants' expectations. The original poster expresses confusion about the problem's ambiguity and the calculations involved.

kingsean
Messages
2
Reaction score
0
I've been working on a problem and I'm stumped :| I'm usually pretty good at deriving the equations for problems and solving them once I find out what I need to be solved. But this one is a bit too ambiguous for me, and I'm looking for a few hints :) Anything is appreciated!

On an essentially friction-less, horizontal ice rink, a skater moving at 3.0m/s encounters a rough patch that reduces her speed by 45% due to a friction force that is 25% of her weight. Use the work-energy theorem to find the length of this rough patch.


I've tried a few methods but, alas, no answer. The back of the book says 1.5m if that is of any assistance.

Thanks again!
 
Physics news on Phys.org
Just solve the problem using "m" for the mass and it should cancel out in the end.

You know the initial energy will just be the kinetic energy ([tex]K[/tex]) and that will equal the final kinetic energy plus work done by friction ( [tex]K[/tex]+[tex]W_f[/tex] )
 
dav2008 said:
Just solve the problem using "m" for the mass and it should cancel out in the end.

You know the initial energy will just be the kinetic energy ([tex]K[/tex]) and that will equal the final kinetic energy plus work done by friction ( [tex]K[/tex]+[tex]W_f[/tex] )


I've taken this into consideration, but my answers still end up being too high or too low :(
 
I worked it out and got 1.46 meters as the answer.

I said that the final velocity was 3*.45 (although the wording would suggest that it should be 3-(3+.45) but that gives me 1.28)

Can you show how you're doing it and what answer you get?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 56 ·
2
Replies
56
Views
5K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
3
Views
5K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
13K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K