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Schrodinger Eqn

by c299792458
Tags: schrodinger
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c299792458
#1
Jun9-11, 07:07 AM
P: 71
Hi, I am new to QM, so advanced apologies for the dumb questions to follow. What does "the spectrum of boundstates is non-degenerate" mean? And why is the time-independent Schrodinger eqn reflection invariant? (I'm not sure I quite know what that means either...)

Thanks!
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alxm
#2
Jun9-11, 08:03 AM
Sci Advisor
P: 1,866
"Degenerate" energy states are ones which have the same energy. So "the spectrum of bound states is non-degenerate" means no two bound states have the same energy.
(This is specific to your system though, and not true in general)
A reflection is a transformation of coordinates x -> -x. So it means that the equation gives the same solutions if you invert the coordinate system.
(which may also include the _time_ coordinate, since it's time-independent, changing the sign of the time coordinate will by definition not change anything.)
c299792458
#3
Jun9-11, 10:50 AM
P: 71
Thanks, alxm!


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