Register to reply 
Schrodinger Eqnby c299792458
Tags: schrodinger 
Share this thread: 
#1
Jun911, 07:07 AM

P: 71

Hi, I am new to QM, so advanced apologies for the dumb questions to follow. What does "the spectrum of boundstates is nondegenerate" mean? And why is the timeindependent Schrodinger eqn reflection invariant? (I'm not sure I quite know what that means either...)
Thanks! 


#2
Jun911, 08:03 AM

Sci Advisor
P: 1,866

"Degenerate" energy states are ones which have the same energy. So "the spectrum of bound states is nondegenerate" means no two bound states have the same energy.
(This is specific to your system though, and not true in general) A reflection is a transformation of coordinates x > x. So it means that the equation gives the same solutions if you invert the coordinate system. (which may also include the _time_ coordinate, since it's timeindependent, changing the sign of the time coordinate will by definition not change anything.) 


#3
Jun911, 10:50 AM

P: 71

Thanks, alxm!



Register to reply 
Related Discussions  
Schrodinger's Cat  Quantum Physics  24  
Schrodinger's cat  Set Theory, Logic, Probability, Statistics  2  
Schrodinger's Cat  Quantum Physics  15  
Schrodinger's ***  Current Events  6  
Instead Schrodinger's Cat  Quantum Physics  1 