Calculate the molarity, M, of the NaOH

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Discussion Overview

The discussion revolves around calculating the molarity of a sodium hydroxide (NaOH) solution based on the titration of potassium acid phthalate (KHP). The context includes a specific experimental setup involving the weights and volumes used in the titration process.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents a calculation for the molarity of NaOH based on the weight of KHP and the volume of NaOH used in the titration.
  • Another participant corrects the molecular weight of KHP, stating it is 204.22 g/mol, which differs from the initial claim of 71.08 g/mol.
  • The first participant acknowledges the correction and expresses gratitude.

Areas of Agreement / Disagreement

There is a disagreement regarding the molecular weight of KHP, with one participant asserting a different value than initially used in the calculation. The discussion does not reach a consensus on the correct molar mass.

Contextual Notes

The initial calculation provided by the first participant is based on an incorrect molecular weight, which affects the resulting molarity calculation. The discussion does not resolve the implications of this error or provide a corrected calculation.

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An amount of potassium acid phthalate (KHP) weighs 0.426 g. The KHP is dissolved in a small amount of water and titrated with 16.98 mL of NaOH. Calculate the molarity, M, of the NaOH.

The following is my answer, but it was wrong. Can anyone help? Thanks

Molecular weight of KHP = 71.08
0.426/71.08/0.01698 = 0.353
 
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The molecular weight of KHP is 204.22 g/mol. Assuming 16.98 mL was the amount needed to reach the end point your calculation is correct except for the molar mass of KHP.
 
Thanks a lot

:smile: :smile: :smile:
 
no problem
 

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