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Using cross product to find angle between two vectors

by yayscience
Tags: angle, cross, product, vectors
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Jun30-11, 12:33 AM
P: 5
1. The problem statement, all variables and given/known data
Find the angle between
\vec{A} = 10\hat{y} + 2\hat{z} \\
and \\
\vec{B} = -4\hat{y}+0.5\hat{z}
using the cross product.

The answer is given to be 161.5 degrees.

2. Relevant equations
\left| \vec{A} \times \vec{B} \right| = \left| \vec{A} \right| \left| \vec{B} \right|sin(\theta)


3. The attempt at a solution
\left| \vec{A} \times \vec{B} \right| = [/tex] [tex]\left|
\hat{x} & \hat{y} & \hat{z} \\
0 & 10 & 2 \\
0 & -4 & 0.5
\end{array} \right| = \left| 13\hat{x} \right| = 13 [/tex]

The magnitude of A cross B is 13.

Next we find the magnitude of vectors A and B:
[tex] \left| \vec{A} \right| = \sqrt{10^2+2^2} = \sqrt{104} = 10.198039 [/tex]
[tex] \left| \vec{B} \right| = \sqrt{(-4)^2+(\frac{1}{2})^2} = \sqrt{16.25} = 4.0311289 [/tex]

multiplying the previous two answers we get:

So now we should have:
[tex] \frac{13}{41.109609} = sin(\theta) [/tex]

Solving for theta, we get:
18.434951 degrees.

This is frustrating: 180-18.434951 = the correct answer. I'm not quite sure where I'm going wrong here.

I must be making the same mistake repeatedly. Another problem was the same thing, but with the numbers changed, and I also got the 180-{the answer I was getting} = {the correct answer}, but when I tried the example using the SAME methodology, I got the correct answer.

Can someone please share some relevant wisdom in my direction?
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Jun30-11, 01:21 AM
HW Helper
P: 10,776
sin(alpha)=sin(180-alpha) Plot the two vectors and you will see what angle they enclose.

I like Serena
Jun30-11, 01:57 AM
HW Helper
I like Serena's Avatar
P: 6,189
You might use the sign of the inner dot product to see which angle you have.

Jun30-11, 03:05 AM
P: 5
Using cross product to find angle between two vectors

I can plot them, and I can see the angle, but I'm interested in calculating the angle.
When I use the dot product I get the correct result, but I cannot see where my mistake is while using the cross product.
Jun30-11, 03:19 AM
HW Helper
P: 10,776
There is no mistake, you get the sine of the angle, but there are two angles between 0 and pi with the same sine.

Jul1-11, 12:30 AM
P: 5
Oh wow; I didn't even consider that the answer wasn't unique.

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