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Eigenvectors and Eigenspace |
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| Jul2-11, 08:40 AM | #1 |
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Eigenvectors and Eigenspace
1. The problem statement, all variables and given/known data
Im looking at finding the eigenvectors of a matrix but also a basis for the eigenspace A = [ 6 16 ] [ -1 -4 ] lambda = 4 lambda = -2 2. Relevant equations (A - lambda I ) v = 0 3. The attempt at a solution So with the above equation I get: for lambda = 4 [ 6 - 4 16 ] [ v1 ] = [ 0 ] [ -1 -4 - 4 ] [ v2 ] [ 0 ] so 2 v1 + 16 v2 = 0 -v1 - 8v2 = 0 so v1 = 8v2 and the basis for the eigenspace is span [ 8 ] [ 1 ] First is that right? because when I put it into an eigenvector calculator on the web it gives me -8 instead of 8 but I cant see how I could get to that. Second if this is the basis for the eigenspace then how can I find the eigenvectors for the eigenvalue? thanks, |
| Jul3-11, 02:51 AM | #2 |
Recognitions:
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ehild |
| Jul3-11, 07:48 AM | #3 |
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Oh yeah thats right thanks.
Is it as simple as the vector is: [-8v2] [v2] and the eigenspace is: span [-8] [1] |
| Jul4-11, 03:26 PM | #4 |
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Eigenvectors and Eigenspace
Sorry I realised this should have been posted in the calculus section would it be possible to have it moved?
I think what I have put above for the eigenspace is correct? But what about the eigenvector I cant seem to understand what this is. |
| Jul4-11, 11:31 PM | #5 |
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(-8,1) multiplied by any number is an eigenvector. You need to find the other one, which belongs to the other eigenvalue lambda=2.
The two eigenvectors are the basis of the "eigenspace". You can choose the normalised vectors as basis. ehild |
| Jul5-11, 12:15 PM | #6 |
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Oh thanks. Do I need to normalise the vectors or is it fine to just find the two vectors and give that?
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| Jul5-11, 12:40 PM | #7 |
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You do not need to normalize in principle.
ehild |
| Jul5-11, 12:47 PM | #8 |
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ok thanks.
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