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Inverse Matrix Proof |
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| Nov2-04, 09:12 PM | #1 |
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Inverse Matrix Proof
I'm having a bit of a struggle with my assignment.
I'm supposed to find what is x in AxB = (B-1A-1)-1 . I'm stumped at what to do with this. My friend said that x is I (identity matrix), but he is unable to prove it as well. My linear algebra class just recently started doing this topic and I haven't fully absorbed the subject yet. Any hints or tips would be helpful though. Thanks! |
| Nov2-04, 11:17 PM | #2 |
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Hi, you should try to simplify the right hand side, starting with the outermost -1. What rules do you have for the inverse of a product of matrices?
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| Nov3-04, 07:05 AM | #3 |
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(B-1A-1)-1 is the matrix C such that C(B-1A-1)= I. Since you have that equal to AxB, how do you get AxB(B-1A-1)= I??
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