|Jul6-11, 02:08 PM||#1|
Statistics, ping pong balls in bag probability question
1. The problem statement, all variables and given/known data
Twelve colored ping-pong balls are placed into a shopping bag and well mixed. There are two red balls, six blue balls and four green balls. One ball is selected at random, its color noted and then it is set aside. A second ball is then randomly selected and its color noted. What is the probability that both balls are the same color?
2. Relevant equations
P(two same color) = P(red) + P(blue) + P(green)
3. The attempt at a solution
P(two same color) = (2/12 + 1/12) * (6/12 + 5/12) * (4/12 + 3/12) = .8125
|Jul6-11, 05:33 PM||#2|
why are you multiplying instead of adding?
and eg what is 6/12+5/12 supposed to be?
Start again …
|Jul6-11, 06:53 PM||#3|
Hi tiny-tim! I'm sorry, I am lost on how to start this equation. Would you be able to guide me a bit through this? Thank you for your help!!!
|Similar Threads for: Statistics, ping pong balls in bag probability question|
|Ping-Pong balls in a room?||Introductory Physics Homework||10|
|How to hallucinate with ping-pong balls and a radio||General Discussion||3|
|New uses for ping-pong balls||General Discussion||4|
|Video object tracking: ping-pong balls||Computing & Technology||1|
|Quantum Ping Pong Balls||Quantum Physics||0|