Accelerating an electron through a pot. diff.

[Romperstomper]

An electron is accelerated through a potential difference of 240V, what is it's speed?

I used energy conservation to find it.

So, here's what I did:
$$0 = \frac{1}{2} m\Delta v^2 + q\Delta V$$

$$240V*(1.6*10^-19C) = \frac{1}{2} * (9.1*10^-31kg )* V^2$$

$$V = 9.2*10^6 m/s$$

Is this correct, or am I doing something wrong?

 

[Doc Al]

Looks good to me.

 

[wais]

Your calculation looks correct to me! Using the equation for energy conservation, you have correctly solved for the electron's final velocity. Just be sure to pay attention to the units - in this case, the velocity should be in meters per second (m/s). Good job!