Simple Pendulum: Oscillating Mass Explained

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The discussion revolves around the concept of a simple pendulum and its characteristics, particularly in relation to a baseball bat suspended from one end. Participants explore the conditions under which an oscillating mass tied to a string can be classified as a simple pendulum versus a physical pendulum.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the definition of a simple pendulum and discuss the necessary conditions for an object to be considered one. There is an exploration of the differences between a simple pendulum and a physical pendulum, with references to mass distribution and string properties.

Discussion Status

The discussion is active, with participants providing insights and clarifications regarding the definitions and conditions related to pendulums. Some have offered specific criteria for classifying pendulums, while others are seeking further understanding of the concepts involved.

Contextual Notes

There is a mention of the need for participants to demonstrate their own thought processes regarding the questions posed, indicating a focus on individual understanding and reasoning in the discussion.

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simple pendulm

If I suspend a baseball bat from one end and let it swing back and forth does it make a simple pendulm?
 
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Under what conditions does an oscillating mass tied to a string constitute a simple pendulum?
 
Please show us that you have but some thought of your own into these questions.
 
I know that a simple pendulum consists of a mass m tied to a string (considered massless) of length L. So If I suspend a baseball bat from one end and let it swing back and forth does it make a simple pendulm
 
No, it will make a physical pendulum.
 
Under what conditions does an oscillating mass tied to a string constitute a simple pendulum?
 
When it's point-mass ([itex]I_{cm} = mr^2[/itex]) tied to the massless string.

Try it:

Physical pendulum Period

[tex]T = 2 \pi \sqrt{\frac{I}{mgd}}[/tex]

Substituting for ([itex]I_{cm} = mr^2[/itex])

[tex]T = 2 \pi \sqrt{\frac{mr^2}{mgd}}[/tex]

[itex]d = l = r[/itex]

[tex]T = 2 \pi \sqrt{\frac{l}{g}}[/tex]
 

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