How Long Should Pilots Fire Engines for Safe Re-entry?

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Homework Help Overview

The discussion revolves around the physics of a space capsule's re-entry into the Earth's atmosphere, specifically focusing on the necessary calculations to determine how long pilots must fire the engines to reduce speed from 2.6 x 10^4 m/s to 1.1 x 10^4 m/s. The problem involves concepts from mechanics, including forces, acceleration, and momentum.

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  • Mixed

Approaches and Questions Raised

  • Participants explore Newton's 2nd Law and its application to the problem, discussing how to relate force, mass, and acceleration. Some express a desire for algebra-based approaches due to difficulties with calculus. Others mention the impulse-momentum theorem as a potential method for solving the problem.

Discussion Status

The discussion is ongoing, with various approaches being suggested. Some participants have provided insights into relevant physics principles, while others are seeking clarification on how to apply these concepts without using calculus.

Contextual Notes

One participant notes their background in algebra-based physics and expresses difficulty with calculus, indicating a preference for solutions that do not require advanced mathematical techniques. The original poster has also indicated a lack of understanding of how to arrive at the provided answer.

pkhor
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For a safe re-entry into the Earth's atmosphere, the pilots of a space capsule must reduce their speed from 2.6 x 10^4 m/s to 1.1 x 10^4 m/s. The rocket engine produces a backward force on the capsule of 1.8 x 10^5 N. The mass of the capsule is 3800 kg. For how long must they fire their engine? [Hint: Ignore the change in mass of the capsule due to the expulsion of exhaust gases.]

The answer to this problem is 320 seconds, but I have no idea how to get to that answer. I just want to know the formula or theorem that I can use to solve this specific problem. Your help would be highly appreciate.

PS. sorry for my English, I'm not a native speaker.
 
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Newton's 2nd Law

[tex]\sum_{i=1}^{n} \vec{F}_{i} = \frac{d \vec{P}}{dt}[/tex]

Using [itex]\vec{p} = m \vec{v}[/itex]

[tex]\sum_{i=1}^{n} \vec{F}_{i} = \frac{d (m \vec{v})}{dt}[/tex]

The problem states mass is constant therefore it can go out of the derivative.

[tex]\sum_{i=1}^{n} \vec{F}_{i} = m \frac{d\vec{v}}{dt}[/tex]

For Finitessimals:

[tex]\sum_{i=1}^{n} \vec{F}_{i} = m \frac{\Delta \vec{v}}{\Delta t}[/tex]
 
My course is Algebra based physics.
I can't understand Calculus, so is there any formula that based on algebra?
Thanks for your respond.
 
pkhor said:
For a safe re-entry into the Earth's atmosphere, the pilots of a space capsule must reduce their speed from 2.6 x 10^4 m/s to 1.1 x 10^4 m/s. The rocket engine produces a backward force on the capsule of 1.8 x 10^5 N. The mass of the capsule is 3800 kg. For how long must they fire their engine? [Hint: Ignore the change in mass of the capsule due to the expulsion of exhaust gases.]

Use F=Ma to find the acceleration due to the backward force. You can then find the time needed to reduce their speed to the correct value.
 
This problem involves manipulating the impulse-momentum theorem.
We know that Impulse is equal to the change in momentum (I=Δp) where change in momentum is Δp=mv(final)-mv(initial). We also know that Impulse is equal to Force*change in time (I=FΔt). Using these formulas you should be able to solve this question with ease.
 

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