Calculating Final Velocity: 1.5kg Cart with 85g Balls vs 255g Ball at 3.5 m/s"

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The discussion focuses on calculating the final velocity of a 1.5 kg cart propelled by either three 85g balls or one 255g ball, both ejected at a speed of 3.5 m/s relative to the cart. The momentum conservation principle is applied, where the initial momentum of the system equals the final momentum after the balls are ejected. The calculations reveal that the cart's final velocity after ejecting three 85g balls is greater than that after ejecting a single 255g ball, confirming the expected outcome based on mass and velocity relationships.

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Momentum Poblem.. Need help!

A 1.5 kg cart is propelled forward by a series of 85g balls being ejected from the rear of the cart with a speed of 3.5 m/s relative to the cart. Calculate the speed of the cart after three balls have been ejected. Compare this to the speed of the cart if it had ejected a signle 255g ball at 3.5 m/s relative to the cart. Assume negligible friction, calculate the final velocity for each cart?

i have got an answer but the relationship is wrong the first cart should have the faster velocity... anyone help i need to understand this!
 
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dishoom said:
A 1.5 kg cart is propelled forward by a series of 85g balls being ejected from the rear of the cart with a speed of 3.5 m/s relative to the cart. Calculate the speed of the cart after three balls have been ejected.

mv=mv
First Ball:
1.415kg(v)=(0.085kg)(3.5m/s)
solve for v then just do the same for second+third

dishoom said:
Compare this to the speed of the cart if it had ejected a signle 255g ball at 3.5 m/s relative to the cart. Assume negligible friction, calculate the final velocity for each cart?

mv=mv
1.245kg(v)=(0.255kg)(3.5m/s)
solve for v
 
umm... that's not it... it's suppose to be relative to the cart.. i know this cause i did something similar to urs and i got it wrong..
and by the way the mass of balls are separate...
 

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