Express in Polar Coordinate


by Tarhead
Tags: coordinate, express, polar
Tarhead
Tarhead is offline
#1
Nov14-04, 10:34 PM
P: 7
How do I express this in polar coordinates?

(x-h)^2+(y-k)^2= h^2+k^2

It is a circle with k and h greater than 0.
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tiger_striped_cat
tiger_striped_cat is offline
#2
Nov14-04, 11:04 PM
P: 51
go to:

http://mathworld.wolfram.com/PolarCoordinates.html

I think the transforms would be

x--> rcos theta
y--> r sin theta
h --> R cos theta'
k --> R sin theta'

4 prameters to describe the points on a shifted circle (shifted orgin because of the k and h terms) in either cartesian or polar coordinates

Not sure, but I think.
James R
James R is offline
#3
Nov15-04, 01:15 AM
Sci Advisor
HW Helper
PF Gold
P: 562
In two dimensions, the transformations are:

[tex]x = r\cos \theta, \qquad y = r\sin \theta[/tex]

That's all you need.

tiger_striped_cat
tiger_striped_cat is offline
#4
Nov15-04, 02:37 AM
P: 51

Express in Polar Coordinate


Yeah this makes sense. Sorry for my mistake. You'll only need two variables to plot a 1-d object in a 2d space.

You would need four parameters to specify a shifted circle in either coordinate system. (The k and h parameters will propagate through your transformation.) You could transform this shift into polar coordinates as well (and you would have to if this was a complicated mechanics problem) but you don't even need to bother with this because it is given as a constant.

Hope I didn't mess you up. Sorry again.


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