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Calculating magnetic flux 
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#1
Sep711, 05:03 AM

P: 446

1. The problem statement, all variables and given/known data
A cube of edge length 0.05m is positioned as shown in the figure below. A uniform magnetic field given by B = (5 i + 3 j + 2 k) T exists throughout the region. a) Calculate the flux through the shaded face. 2. Relevant equations [itex]\phi[/itex] = B.A cos [itex]\theta[/itex] 3. The attempt at a solution The area would simply be 0.0025m^2 I'm having trouble understanding how to get the angle and also how to interpret the given magnitude of the magnetic field, it's a vector quantity. I thought at first the way to get the angle was to assume that the surface of the cube could be considered a vector as well, that way it would only have the j component since it's only got a direction in the yaxis. Then using the formula for the angle between two vectors, I got 53.5 degrees, though I'm not too sure how to use the given magnetic field value. 


#2
Sep711, 06:48 AM

Sci Advisor
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P: 26,148

Hi NewtonianAlch!
just do the inner product! (dot product)the area can be represented by a vector of magnitude A in the normal direction, so just "dot" that with the field, and that's your flux! (or you can "dot" it with the unit normal, and then multiply by the area … same thing) 


#3
Sep711, 07:47 AM

P: 446

Hi tinytim,
Do you mean to say: (5, 3, 2)[itex]^{T}[/itex].0.0025 which is (5*0.0025 + 3*0.0025 + 2*0.0025) B.A 


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