Calculating Gravitational Attraction: Solving for the Answer

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Homework Help Overview

The discussion revolves around calculating gravitational attraction between two objects, specifically two textbooks with a given mass and distance apart. The subject area is gravitational physics, focusing on the application of Newton's law of universal gravitation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to apply the gravitational force formula, F=Gm1m2/r^2, but express confusion about how to manipulate the formula to arrive at the answer provided in the textbook. There are questions regarding the correct interpretation of the formula and the significance of the distance squared in the calculation.

Discussion Status

Some participants are providing guidance on plugging in the values into the formula, while others are questioning the correctness of the formula used. There is a mix of understanding and confusion, with no clear consensus on the steps to take next.

Contextual Notes

Participants express uncertainty about the problem setup and the application of the formula, indicating a need for clarification on how to proceed with the calculations. The original poster references a specific example from a textbook, which may impose constraints on the discussion.

Jimsac
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Here is the ex. in the book. Two 3.kg textbooks are .15 apart. What is the gravitational attraction?
The answer is given 2.7*10-8
I also know the formula is F=Gm1m2/r
I just do not understand what they are doing to get the answer.

(6.67*10-11 N-m2kg2)(3.kg)(3.kg)/.15
This is the formula I am trying to use

Please help!
 
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It's
[tex]F=\frac{m_1m_2G}{r^2}[/tex]
distance squared.
 
I know the formula I do not understand how to solve it
 
Jimsac said:
I know the formula I do not understand how to solve it

Look closer. Your formula is wrong, and Nate's is right (note the "r2" in the denominator).
 
misunderstood

What I do not understand is what to do with the formula. How do you solve this problem? THis is just an example in the book with the answer given but I do not understand what to do with the formula to solve it. Sorry
 
Plug in the numbers:
[tex]F=\frac{m_1m_2G}{r^2} \Rightarrow \frac{3 \times 3 \times (6.67 \times 10^{-11})}{0.15^2}[/tex]
 

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