Are My Partial Derivatives Correct for Linearization?

Click For Summary
SUMMARY

The discussion centers on the linearization of the function f(x,y,z) = ln(xy) + yzcos(xz) at the point (1,1,π/2). The correct partial derivatives calculated at this point are fx = 1 - (π/2)², fy = 1, and fz = -π/2. The linearization formula is applied to estimate the change in the function value when moving to the point (1.1, 1.2, π/2 + 0.2). The final result confirms that fz at the specified point is -π/2, not π/2.

PREREQUISITES
  • Understanding of partial derivatives in multivariable calculus
  • Familiarity with the concept of linearization of functions
  • Knowledge of the natural logarithm and trigonometric functions
  • Ability to perform calculations involving Taylor series expansions
NEXT STEPS
  • Study the application of Taylor series in multivariable functions
  • Learn about the implications of linearization in real-world scenarios
  • Explore the use of partial derivatives in optimization problems
  • Investigate the properties of logarithmic and trigonometric functions in calculus
USEFUL FOR

Students and professionals in mathematics, particularly those studying calculus, as well as engineers and scientists who apply linear approximations in their work.

DeadxBunny
Messages
29
Reaction score
0
Original question: Let f(x,y) = ln(xy) + yzcos(xz). Find the linearization of f at the point (1,1,pi/2). Use this linearization to estimate the change in the value of the function resulting from moving from (1, 1, pi/2) to (1.1, 1.2, pi/2 + 0.2).

I believe the first steps to completing this problem are finding the partial derivatives of x, y and z at the point (1, 1, pi/2) which I have done:
fx = 1 – (pi/2)^2
fy = 1
fz = pi/2
Are these correct?

If so, what do I do next?
 
Physics news on Phys.org
You just need to use this:

[tex]f(x, y, z) = f(x_0, y_0, z_0) + f_x (x-x_0) + f_y (y-y_0) + f_z (z-z_0) +O(\Delta^2)[/tex]
 
fz(1, 1, pi/2)= -pi/2, not pi/2.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
3
Views
993
Replies
64
Views
7K