Why Do Double Bonds Not Allow Bond Rotation?

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Discussion Overview

The discussion revolves around the reasons why double bonds in organic chemistry do not allow for rotation, contrasting this with the behavior of single bonds. Participants explore the implications of bond structure, energy considerations, and the behavior of electrons in bonding scenarios.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant suggests visualizing bonds in three dimensions, noting that single bonds are formed by overlapping s-orbitals while double bonds involve parallel p-orbitals, which hinder rotation due to loss of overlap.
  • Another participant questions the nature of double bond rotation, asking whether it is impossible or merely resistant, indicating a need for energy to break the pi bond.
  • A participant raises a question about the delocalization of p orbital electrons in forming pi bonds, challenging the order of electron involvement based on energy levels.
  • It is proposed that electrons seek the lowest energetic configuration, with s orbitals being lower in energy than p orbitals, influencing the bonding process in alkenes.

Areas of Agreement / Disagreement

Participants express differing views on the mechanics of bond rotation and the behavior of electrons in bonding, indicating that multiple competing perspectives remain without consensus.

Contextual Notes

Some assumptions regarding the energy required for bond rotation and the behavior of electrons in bonding are not fully explored, leaving certain aspects unresolved.

Cheman
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Why in organic chemistry do double bonds not allow rotation of bonds, whilst single bonds do?

Thanks. :smile:
 
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Picture bonds in three dimensions to explain things like this. A single bond will be created by the area of intersection between the axial s-orbitals, which point toward each other. A double bond, on the other hand, is created by the overlap of parallel vertically-oriented p-orbitals. If you rotate the atoms relative to each other, the s-orbital continue to overlap as before, while the p-orbitals take on what you could call a staggered position (when viewed from the side), so overlap does not exist.
 
Ok, so they rotate polarised light - my questions now are:

a) Why? How do they cause it to rotate?

b) Why do they turn it the opposite ways?

Thanks. :smile:
 
Sorry - put that on the wrong one of my posts! :rolleyes:

The question on THIS post should be "So, what happens if you try to rotate a double bond? Does it resist rotation or is it still possible?"

Thanks. :smile:
 
Rotating the double bond would eliminate the overlap between the p-orbitals, as Sirus described. You would need enough energy to break the C-C pi bond, which isn't common at normal temperatures. It is possible, however, at high temperatures.
 
Why is it though that the p orbital electrons are the ones which become delocalised and form the pi bonds after the other electrons in the outer shell have formed sigma bonds with 2 hydrogens and the other carbon? After, surely we would expect the electron with the highest energy to react first ie the p orbital - not the s orbitals?

Thanks. :smile:
 
The electrons are trying to adopt the lowest possible energetic configuration though, right? S orbitals are lower energy than p orbitals, so the lower energy molecular orbitals will have a larger contribution from the s atomic orbitals. In the case of an alkene the last p orbital is what is "left over."
 

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