Find the final temperature of the ball

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Homework Help Overview

The problem involves determining the final temperature of a copper ball that has been heated, given its initial dimensions and the change in size due to thermal expansion. The subject area relates to thermal physics and material properties, specifically thermal expansion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the coefficient of linear expansion for copper and its relation to volume expansion. There are questions about the application of the volume expansion formula and concerns about the calculations leading to unexpected results.

Discussion Status

The discussion includes attempts to apply the formula for volume change due to temperature variation. Some participants express uncertainty about their calculations and the correct application of the initial temperature. There is a mention of a correction made regarding the addition of the initial temperature.

Contextual Notes

Participants are working under the assumption of a room temperature of 22°C and are exploring the implications of the thermal expansion coefficients for copper. There is also a reference to the specific dimensions of the ball and the change in size that has been observed.

dphoos
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A copper ball with a radius of 1.5 cm is heated until its diameter has increased by 0.20 mm. Assuming a room temperature of 22°C, find the final temperature of the ball.
 
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What have you tried?
 
well, I know that the coefficient of linear expansion for copper is 17 x 10^-6, so it's coefficient of volume expansion is 3 times that.. and I know that the volume has changed by about .54. I'm not really sure what to do with this though
 
I assume I'm using the equation delta V = BV(delta T), but when I do this I get a huge number
 
nevermind, I got it. I was subtracting 22 instead of adding it. The answer is 410.27 right?
 

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