Two Oscillator Frequencies on the moon

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Homework Help Overview

The discussion revolves around the frequencies of two simple harmonic oscillators—a vertical spring and mass, and a pendulum—when transitioning from Earth to the Moon. The original poster presents a problem involving the calculation of new frequencies given the change in gravitational acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the new frequency of both oscillators by first determining the period and then using gravitational acceleration. Some participants question how the frequencies depend on the value of g, suggesting that understanding this relationship could simplify the problem.

Discussion Status

Participants are exploring different approaches to the problem. One participant suggests that the frequency of the spring and mass is independent of g, while another indicates that the frequency of the pendulum is directly proportional to the square root of g. The original poster acknowledges some assistance but also indicates they have resolved the issue independently.

Contextual Notes

There is mention of the gravitational acceleration values for Earth and the Moon, which are critical to the calculations being discussed. The original poster expresses difficulty in arriving at the correct answers despite multiple attempts.

mikezietz
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Two different simple harmonic oscillators have the same natural frequency (f=2.80 Hz) when they are on the surface of the Earth. The first oscillator is a vertical spring and mass, the second is a pendulum. If both systems are moved to the surface of the moon (g=1.67 m/s2), what is the new frequency of the vertical spring and mass?

Calculate the new frequency of the pendulum. ?



This is the question. For it i just used the frequency to find the period, i then used this to find the length of the pendulum, i think solved with the new g, to find the period, and then solved back to find the new frequency, i tried this several times, and i cannot seem to get to the new frequency. I have tried similar things with the spring and mass, but i cannot find the right equations to find it.
 
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How, exactly, do the frequencies of the two oscillators depend on g? If you know that then the problem reduces to ratios and proportions.
 
Yes but it's not giving me the right answer, is there another way to go about this problem?
 
For the spring and mass, the frequency is independent of the value of g. So, it remains the same.

And for the pendulum, instead of doing this long calculation, just see that the frequency is directly proportional to the square root of the value of g.
So,

[tex]\frac{f_m}{f_e}=\sqrt{\frac{g_m}{g_e}}[/tex]

Hope that helps!

spacetime
www.geocities.com/physics_all
 
thanks, it would have helped, but i finally figured it out myself :) you are correct sir in your help
 

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