|Oct28-11, 07:17 PM||#1|
What to use when reverse chain rule doesnt work?
My equation to solve is (xy+(x^2))dx + (-1)dy=0
For method of exact solutions, the partials are not equal to each other so I cannot use
exact solutions (reverse chain rule)
I dont know how to solve this
|Oct29-11, 08:12 AM||#2|
What is reverse chain rule?
Any equation is exact in some coordinates so find them.
you stated (correctly)
(xy+x2)y - (-1)x
is not zero but we can use the fact that
to conclude that the equation is exact in
∫((xy+x2)y - (-1)x)/(-1)∂x
and y since (xy+(x2))dx + (-1)dy can be written
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