Finding Mass of Bicyclist and Bike for Unbanked Curve Travel

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Homework Help Overview

The problem involves determining the smallest radius of an unbanked curve that a bicyclist can navigate at a speed of 18 mph, given a coefficient of static friction of 0.32. The discussion revolves around the necessity of knowing the mass of the bicyclist and the bike to solve the problem.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of a free body diagram and centripetal force equations. Questions arise regarding how to find the mass of the bike and rider, with some suggesting that mass can be treated as a variable that cancels out in the equations.

Discussion Status

Participants are exploring different approaches to handling the mass variable in the equations. Some have provided guidance on using symbolic representation, while others express confusion about the requirement to work in symbols. There is no explicit consensus on the best approach, but several participants are encouraging the use of symbolic notation.

Contextual Notes

There is mention of a teaching approach that emphasizes working with symbols rather than numerical values until the final steps, which some participants find confusing. The discussion reflects a common challenge in physics problems where mass is a variable that can complicate the setup.

AllAmericanGirl2004
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Here's the Prob:

What is the smallest raduis of an unbanked curve around which a bicyclist can travel if her speed is 18 mph and the coefficient of static friction between the tires and the road is .32?


This was the response I got:

For the second one: draw a freebody diagram, label all the forces, then use the centripetal force equation F=(mv^2)/r to find the radius.

Now...here's my question:


Thanks, but wait, I'm still a little confused on the bike problem. We need to know the mass of the bike and the rider, and that's something we don't know yet. How do you find the mass? wait...tell me if I'm doing this right...

g=gravity? So to find the mass would you use the equation g=G*me/re^2?? If not...still, how is the mass found??
 
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Just use the symbol m for mass and you will find that it cancels out in the end. Also, g is the local acceleration due to gravity which you can look up (certainly your textbook displays its value).

Now go back and try to follow the original advice!
 
The mass will drop out once you combine equations.

This whole mass thing is a common problem. You have two choices: write out the equations in terms of a variable m for mass and see that they cancel eventually, or make up a value of mass and trust me that they cancel. I don't think I'd trust me if I were you.

--J
 
Thanks Soooooooo Much!
 
Dejavu!

I don't know if your prof/teacher is stressing that everything should be done in symbols until the last step. Even simple things like F=ma stuff. Once you get good at notation and solving in symbols you'll understand the units and what's going on more. You'll also be able to quicklly find if and where you made mistakes in canceling or simple algebra. (It also makes following your work eaiser to others i.e. tutors)

-Burg
 
uh, yeah. He kind of makes us do all the symbolism junk. It confuses me more than it should. Thanks for the advice. It'll come in handy later.
 
Symbols are a godsend to somebody reading over your work. It saves them the trouble of having to guess what you did and then having to actually go and calculate it out to see if that's what you actually did. In particular, if one of the steps is wrong, you could confuse the reader so much that all he can say is "I have no idea how you got this number."

It also helps because calculating numbers takes extra time and extra tools (calculator?) than just reviewing symbols. I think you'll find that many people are more amenable to going over your work if they're not made to do it all over again, too. Although a good tutor really will work the problem on his own beforehand, I doubt you'll find many people doing it for free that are so dedicated to work that isn't their own.

--J
 

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