Waves Interference and Wavelength Calculations

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SUMMARY

The discussion focuses on calculating fringe separation in a double-slit experiment and determining wavelengths for specific interference patterns. Joe presents three scenarios involving light and water waves, including a calculation for fringe distance when light of 400 nm wavelength passes through slits 0.05 mm apart in water. The refractive index of water (1.33) is crucial for adjusting the wavelength. Additionally, the discussion addresses finding a wavelength that results in a minimum at the same location as a second-order maximum for blue light (460 nm) and determining the position for minimal wave action in a water tank experiment.

PREREQUISITES
  • Understanding of wave interference principles
  • Knowledge of the double-slit experiment
  • Familiarity with the concept of wavelength and refractive index
  • Basic skills in solving equations related to wave behavior
NEXT STEPS
  • Calculate fringe separation using the formula for double-slit interference in a medium
  • Explore the relationship between wavelength and refractive index in wave propagation
  • Investigate conditions for destructive interference in wave mechanics
  • Learn about the principles of wave action and standing waves in fluid dynamics
USEFUL FOR

Students and educators in physics, particularly those studying wave mechanics, optics, and interference patterns. This discussion is beneficial for anyone looking to deepen their understanding of light behavior in different mediums and wave interactions.

josephcollins
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Hi ppl, could someone please give me a hand with these:

Light of wavelength 400 nm in air falls on two slits 0.05 mm apart. The slits are immersed in water, as is a viewing screen 40cm away. How far apart are the fringes on the screen?(n water is 1.33)

In a double slit experiment it is found that blue light of wavelength 460nm gives a second order maximum at a certain location on the screen. What wavelength of visible light would have a minimum at the same location?

In a water tank experiment, water waves aee generated with their crests 2.5cm apart and parallel. They pass through two openings 5cm apart in a long wooden board. If the end of the tank is 2m beyond the boards, where would you stand, relative to the "straight through" direction, so that you received little or no wave action?

Thanks for any help,
Joe
 
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Is it you don't know how to do this, or is it you just can't be bothered. First show us an attempt at the question, some working out to where you go to, and we'll give you some hints, tips, and bits of information that will help you out
 
okay, for the first question, I have managed to work it out myself having calculated the new wavelength.

For the others, it's how to set up an equation bearing in mind the condition for destructive interference that I can't work out.
 

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