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the mean of a sum of variables. |
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| Nov4-11, 03:38 PM | #1 |
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the mean of a sum of variables.
How do I prove that the mean of a random variable Z which is the sum of to other random variables X and Y is the sum of the mean of X with the mean of Y?
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| Nov4-11, 03:48 PM | #2 |
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Recognitions:
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Essentially the theorem is equivalent to the theorem that the integral of a sum is the sum of the integrals.
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| Nov4-11, 03:54 PM | #3 |
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well I obviously know that the integral of the sum is the sum of the integral but I don't know how I can relate that to the situation a mentioned, can you please be more specific?
I'm trying to prove it and I'm getting a convultion integral so far... thank you. |
| Nov4-11, 09:58 PM | #4 |
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the mean of a sum of variables.Another approach that would work for the non-independent case is to consider separately the joint distribution and marginal distributions of X and Y. |
| Nov5-11, 04:06 AM | #5 |
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well but I'm not being able to prove it either for dependent or independent variables, can you please show me the proof or tell me where I can find it? thank you
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| Nov5-11, 04:03 PM | #6 |
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Recognitions:
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Two random variables.
E(X+Y)=∫∫(x+y)dF(x,y)=∫∫xdF(x,y) + ∫∫ydF(x,y). Integrate with respect to y in the first integral and integrate with respect to x in the second integral. You will be left with E(X) + E(Y). In the above F(x,y) is the joint distribution function. |
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