When reactions occur, how can you differentiate between A2B2 and 2AB?

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SUMMARY

The discussion clarifies the differentiation between the products of a double replacement reaction, specifically Na2SO4 + CaCl2. The correct product is determined to be CaSO4 + 2NaCl, rather than CaSO4 + Na2Cl2. The rationale is based on the principle that compounds typically simplify to their lowest whole-number ratios, which minimizes energy. A2B2 structures are rare in inorganic chemistry, with hydrogen peroxide being a notable exception.

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Take this double replacement reaction for example:

[tex]Na_2SO_4 + CaCl_2[/tex]

How am I supposed to tell whether the product will be [tex]CaSO_4 + Na_2Cl_2[/tex] or [tex]CaSO_4 + 2NaCl[/tex]?

Obviously, there's a difference between Calcium Sulfate + 2 Sodium Chloride molecules and Calcium Sulfate + Sodium DiChloride, but how can I figure out which it will be?

Thanks for any help,
Jacob
 
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A2B2 (almost) never exists. Whenever the numbers of different atoms in a molecule have a common divisor, you divide by that number to reduce it to the simplest ratio. Why ? Because in most cases, it can be shown that the simplified structure (AB rather than A2B2) is the energy minimizing structure.

So it's extremely rare to find (inorganic) molecules like A2B2, A2B4, A3B6, A2B2C4, etc. Hydrogen peroxide is a notable exception, but then again, peroxide linkages are usually quite unstable.

So, in your specific problem, the product formed is 2NaCl (not Na2Cl2).
 
The products will be [tex]CaSO_4 + 2NaCl[/tex] Why would you get [tex]Na_2Cl_2[/tex]? Sodium ions have a charge of +1 and Chloride ions have a charge of -1. It only takes 1 sodium ion to go with 1 chloride ion.
 

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