Thermo Q: S2-S1=0? Why Doesn't Equation Yield 0?

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SUMMARY

The discussion centers on the concept of entropy change in a device operating at steady state, specifically questioning whether the change in entropy (S2-S1) equals zero. It is established that S2-S1 does not equal zero, as indicated by the equation S2-S1 = s(degree)(T2) - s(degree)(T1) - R ln(p2/p1). This equation demonstrates that entropy change is influenced by temperature and pressure variations, thus confirming that S2-S1 can be non-zero even in steady-state conditions.

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eku_girl83
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For a device operating at steady state, is the change in entropy (S2-S1) equal to 0?
If it is equal to 0, then why doesn't the s2-s1=s(degree)(T2)-s(degree)(T1) - R ln (p2/p1) equation yield 0?

I'm confused on this point...
Any help greatly appreciated!
 
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eku_girl83 said:
For a device operating at steady state, is the change in entropy (S2-S1) equal to 0?


That's False. Where have you seen it?
 

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