The discussion revolves around calculating the horizontal distance (dx) for an object projected at an initial velocity of 100 m/s from angles ranging from 20 degrees to 70 degrees in 5-degree increments. The subject area includes projectile motion and kinematics.
Several participants have provided insights into the calculations needed for the problem, including the breakdown of velocity components and the use of kinematic equations. There is an ongoing exploration of how to systematically approach the problem for multiple angles, with no explicit consensus reached yet.
Participants are assuming ideal conditions, such as neglecting air resistance, and are discussing the implications of using specific angles in their calculations. There is mention of using a variable to represent angles in a general formula.
Skotster said:break up your Vi=100m/s at 20 degrees into the x&y components
Vix=Vi*cos(20 degrees)
Viy=Vi*sin(20 degrees)
assuming you are on Earth and ingoring air friction
use
Vf=Vi+(-9.8m/s^2)*t
to get
t=(Vf-Vi)/(-9.8m/s^2)
lettin Vf=0 to find time to max height
double it to get the total air time
use total time in
dx=Vix*t