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schapman22
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Why doesn't substitution work to find 0∫2 sqrt(4-x^2). I kn ow you can find the integral in other ways. I am just curious why regular substitution won't work. Thank you in advance.
schapman22 said:Why doesn't substitution work to find 0∫2 sqrt(4-x^2). I kn ow you can find the integral in other ways. I am just curious why regular substitution won't work. Thank you in advance.
schapman22 said:Why doesn't substitution work to find 0∫2 sqrt(4-x^2). I kn ow you can find the integral in other ways. I am just curious why regular substitution won't work. Thank you in advance.
Substitution is a valid method for solving equations, but it may not always be the most efficient or accurate method. Depending on the complexity of the problem and the variables involved, other methods such as elimination or graphing may be more appropriate.
No, substitution can only be used for linear equations, where the variables have a power of 1. It cannot be used for equations with variables raised to a higher power, such as quadratic or cubic equations.
You can use substitution when you have two or more equations with the same number of variables and the coefficients of the variables are the same. This allows you to solve for one variable in one equation and substitute it into the other equations to find the values of the remaining variables.
One drawback of using substitution is that it can be time-consuming, especially for equations with multiple variables. It also may not always provide an exact or accurate solution, as rounding errors can occur when substituting values into the equations.
Yes, substitution can be used in real-world problems, especially when dealing with systems of linear equations. It can be used to find the intersection point of two lines, which can represent real-world situations such as finding the break-even point in a business or the optimal solution to a manufacturing problem.