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Thermodynamic derivation of heat capacity

by tarletontexan
Tags: capacity, derivation, heat, thermodynamic
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tarletontexan
#1
Dec11-11, 10:36 PM
P: 30
1. The problem statement, all variables and given/known data

cp=cv+TV?^2/?

2. Relevant equations


cp=T/N([itex]\partialS[/itex]/[itex]\partialT[/itex])p
3. The attempt at a solution
I have the equation, just not sure how to apply it? Any help would be appreciated
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Andrew Mason
#2
Dec11-11, 11:07 PM
Sci Advisor
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P: 6,654
Quote Quote by tarletontexan View Post
1. The problem statement, all variables and given/known data

cp=cv+TV?^2/?

2. Relevant equations


cp=T/N([itex]\partialS[/itex]/[itex]\partialT[/itex])p
3. The attempt at a solution
I have the equation, just not sure how to apply it? Any help would be appreciated
I am not sure what the question is. Are we dealing with an ideal gas?

AM
tarletontexan
#3
Dec11-11, 11:55 PM
P: 30
yes, I know that there are several maxwell relations to get to the solution I just dont know how to apply them.

Andrew Mason
#4
Dec12-11, 09:00 AM
Sci Advisor
HW Helper
P: 6,654
Thermodynamic derivation of heat capacity

Quote Quote by tarletontexan View Post
yes, I know that there are several maxwell relations to get to the solution I just dont know how to apply them.
Start with:

TdS = dU + PdV

CP = (∂Q/∂T)P = T(∂S/∂T)P = (∂U/∂T)P + P(∂V/∂T)P

AM


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