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thermodynamic derivation of heat capacity |
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| Dec11-11, 10:36 PM | #1 |
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thermodynamic derivation of heat capacity
1. The problem statement, all variables and given/known data
cp=cv+TV?^2/? 2. Relevant equations cp=T/N([itex]\partialS[/itex]/[itex]\partialT[/itex])p 3. The attempt at a solution I have the equation, just not sure how to apply it? Any help would be appreciated |
| Dec11-11, 11:07 PM | #2 |
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Recognitions:
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AM |
| Dec11-11, 11:55 PM | #3 |
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yes, I know that there are several maxwell relations to get to the solution I just dont know how to apply them.
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| Dec12-11, 09:00 AM | #4 |
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Recognitions:
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thermodynamic derivation of heat capacityTdS = dU + PdV CP = (∂Q/∂T)P = T(∂S/∂T)P = (∂U/∂T)P + P(∂V/∂T)P AM |
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