Balanced Combustion Equations for Alcohols

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Discussion Overview

The discussion focuses on the balancing of combustion equations for various alcohols, including methanol, ethanol, and other alcohols. Participants seek to verify the correctness of these equations and share methods for checking balance.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents several balanced combustion equations for different alcohols and requests confirmation of their correctness.
  • Another participant suggests a method for verifying the balance of chemical equations by comparing the total number of carbons and hydrogens to the products formed.
  • A later reply reiterates the verification method and expresses a desire for confirmation of the initial equations, indicating confidence in their balancing skills.
  • Two participants express agreement with the initial equations but acknowledge the possibility of making mistakes during their review process.

Areas of Agreement / Disagreement

Participants generally agree that the equations appear to be balanced, but there is an acknowledgment of the potential for error in the verification process. No definitive consensus on the correctness of each equation is reached.

Contextual Notes

Some participants mention the possibility of making mistakes during their calculations, indicating that the verification process may not be foolproof.

The Bob
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I simply want to check that these equations are balanced correctly:

[tex]2CH_3OH_{(g)} + 3O_2_{(g)} \rightarrow 2CO_2_{(g)} + 4H_2O_{(l)}[/tex]

[tex]CH_3CH_2OH_{(g)} + 3O_2_{(g)} \rightarrow 2CO_2_{(g)} + 3H_2O_{(l)}[/tex]

[tex]2CH_3CH(OH)CH_3_{(g)} + 9O_2_{(g)} \rightarrow 6CO_2_{(g)} + 8H_2O_{(l)}[/tex]

[tex]CH_3(CH_2)_2CH_2OH_{(g)} + 6O_2_{(g)} \rightarrow 4CO_2_{(g)} + 5H_2O_{(l)}[/tex]

Thanks.

The Bob (2004 ©)
 
Last edited:
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The easy way to be sure about if your reactions have been successfully balanced, put the number of total carbons to carbon dioxide; and put the hydrogens' total number, multiplied with 0.5 to water. This will do it. As a last step, add the oxygens of carbon dioxide and water, and divide it to 2 and write it before oxygen. This is it!
 
chem_tr said:
The easy way to be sure about if your reactions have been successfully balanced, put the number of total carbons to carbon dioxide; and put the hydrogens' total number, multiplied with 0.5 to water. This will do it. As a last step, add the oxygens of carbon dioxide and water, and divide it to 2 and write it before oxygen. This is it!
This is what I did. I can balance equations I was just wondering if someone could check them and say they think they are right as well because I believe they are.

Thanks

The Bob (2004 ©)
 
Seems OK. Excluding the chance of me during my fast scan making exactly the same mistake as you when calculating it the first time.
(Thought I'd make at least one mistake, maybe something must be wrong anyway then :wink: )
 
osskall said:
Seems OK. Excluding the chance of me during my fast scan making exactly the same mistake as you when calculating it the first time.
(Thought I'd make at least one mistake, maybe something must be wrong anyway then :wink: )
Cheers. :smile:

The Bob (2004 ©)
 

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