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Projectile Motion comparing height and initial velocity 
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#1
Jan1212, 11:19 AM

P: 20

Hey,
I came across this question in my text book, and there isnt an answer for it in the back, so I would just like to check if I have my head around it. The question is: 2 projectiles are launched at the same angle. Projectile 1 reaches a max height of twice that of the projectile 2. What is the ration of the initial speeds? I said that they where in the ratio 4:1, as one of the formulas is: y=yo +voyt 0.5gt^2 and because the height is doubled, the time taken must also be doubled? am I correct in saying this? Thanks 


#2
Jan1212, 11:28 AM

Mentor
P: 41,489

Come up with a formula that relates max height with initial velocity without the need for the time. 


#3
Jan1212, 12:37 PM

P: 20

I got an answer or root(2), is this correct?



#5
Jan1212, 12:51 PM

P: 20

Thank you very much!



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