The Vector Nature of Newton's Second Law

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SUMMARY

The discussion focuses on calculating the acceleration of a 2.0 kg block on a smooth inclined plane at a 15-degree angle. The gravitational force acting on the block is 20 N. The correct approach to find the acceleration involves using the formula for the component of gravitational force acting parallel to the incline, which is calculated as mg sin(theta). The absence of friction is confirmed by the term "smooth plane," simplifying the calculation to a = g sin(theta).

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Basic trigonometry, specifically sine functions
  • Knowledge of gravitational force calculations
  • Familiarity with inclined plane physics
NEXT STEPS
  • Study the application of Newton's Second Law in various scenarios
  • Learn about the effects of friction on inclined planes
  • Explore the concept of gravitational force components
  • Investigate different angles of inclination and their effects on acceleration
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of motion on inclined surfaces.

thomasrules
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A block of mass 2.0kg is placed on a smooth plane, inclined to the horizontal at an angle of 15degrees. The force of gravity, acting straight down on the block, is 20N.
a) What is the acceleration of the block down the plane?

I'm having trouble with this because I know:
Net F=fgcostheta-friction
or fgcostheta-friction=ma=2a

BUT THERE IS NO FRICTION GIVEN NOR A COEFFICIENT OF FRICTION

If anyone knows the answer please share

THanks
 
Last edited:
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Of course you don't have a coefficient of friction. A smooth plane implies no friction! Also, the component of the weight acting parallel to the plane is mgsin theta.
 
Last edited:
Ya I'm a real dumbass I also made a 2 other dumb mistakes...i used fgcostheta instead of fgsintheta...THANKS ANYWAY ! grrrrrrrrrrrrrrrrrrrr
 

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