- #1
CAT 2
- 44
- 1
Homework Statement
A child pushes a block of wood with a mass of 0.72 kg across a smooth table. The block starts from a position of rest and after 2 seconds its has a velocity of 1.6 m/s [forward]
The coefficient of friction is 0.64.
a) Find the net force acting on the block of wood.
b) Find the force of friction acting on the block of wood.
c) Find the force with which the child actually pushes on the block of wood.
Homework Equations
F = ma
F friction = u Fn
The Attempt at a Solution
a)
(I already calculated acceleration, it is 0.8m/s^2)
Using:
F = ma
F = (0.72kg) (0.8m/s^2)
F = 0.576N
This the net horizontal force exerted on the block of wood. b)
Then I figured that the frictional force is: (I figured that Fn = 7.06N)
F friction = u Fn
F friction = (0.64) (7.06N)
F friction = 4.52Nc) And so the applied force must be 4.52N + 0.58N = 5.1N
Correct? Thanks in advance!