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Commutators of vector operators |
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| Jan19-12, 02:23 AM | #1 |
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Commutators of vector operators
I've been trying to work out some expressions involving commutators of vector operators, and I am hoping some of y'all might know some identities that might make my job a little easier.
Specifically, what is [itex]\left[\mathbf{\hat A}\cdot\mathbf{\hat B}, \mathbf{\hat C}\right][/itex]? Are there any useful identities to express this in terms of simpler commutators? Any help is appreciated. |
| Jan22-12, 05:21 PM | #2 |
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Are you sure you mean a "vector operator", typically we talk about matrix operators when discussing the commutator relationships (or group elements in a more general setting).
Vector operator: http://en.wikipedia.org/wiki/Vector_operator However, your question is straightforward, [S,T] = ST - TS (by definition) Start with [AB,C] = ABC - CAB (+ ACB - ACB ) = ABC - ACB + ACB - CAB = A(BC - CB) + (AC - CA)B = A[B,C] + [A,C]B Therefore we conclude [AB,C] = A[B,C] + [A,C]B to be an identity. Does that answer your question.... you could have looked anywhere on the internet to get this.... so I'm guessing this isn't what you want. |
| Jan22-12, 05:27 PM | #3 |
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You can also construct an identity using the so called anti-commutator: http://mathworld.wolfram.com/Anticommutator.html
You should probably do this for practice. |
| Jan22-12, 09:52 PM | #4 |
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Commutators of vector operators
Thank you for the
I would think that you should define [itex][{\bf{\hat S}},{\bf{\hat T}}] = {\bf{\hat S}} \cdot {\bf{\hat T}} - {\bf{\hat T}} \cdot {\bf{\hat S}}[/itex], and therefore start your derivation with [tex][{\bf{\hat A}} \cdot {\bf{\hat B}},{\bf{\hat C}}] = ({\bf{\hat A}} \cdot {\bf{\hat B}}){\bf{\hat C}} - {\bf{\hat C}}({\bf{\hat A}} \cdot {\bf{\hat B}}).[/tex] But from there, I'm not sure how you can safely proceed, if you're being rigorous with your dots and parens. For instance — and correct me if I'm wrong on this — but I don't think [itex]({\bf{\hat A}} \cdot {\bf{\hat C}}){\bf{\hat B}}[/itex] is equal to [itex]{\bf{\hat A}}({\bf{\hat C}} \cdot {\bf{\hat B}})[/itex], so your next step seems iffy. |
| Jan23-12, 04:32 AM | #5 |
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Yeah, sorry I don't know. I thought you were intending for matrix operators. Good luck.
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| commutator, dot product, identities, vectors |
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